Physics Lab

Vector Addition

Adding vectors is fundamentally different from adding scalars: direction matters. Three classical graphical laws and one algebraic method cover all cases.

Concept

Triangle Law

To add A⃗+B⃗\vec{A} + \vec{B}: place tail of B⃗\vec{B} at head of A⃗\vec{A}. The resultant R⃗\vec{R} goes from tail of A⃗\vec{A} to head of B⃗\vec{B}.

Parallelogram Law

Place A⃗\vec{A} and B⃗\vec{B} tail-to-tail. Complete the parallelogram. The diagonal from the common origin is R⃗\vec{R}.

For two vectors of magnitudes AA, BB with angle θ\theta between them: R=A2+B2+2ABcos⁡θR = \sqrt{A^2 + B^2 + 2AB\cos\theta} tan⁡α=Bsin⁡θA+Bcos⁡θ\tan\alpha = \frac{B\sin\theta}{A + B\cos\theta} where α\alpha is the angle of R⃗\vec{R} with A⃗\vec{A}.

Polygon Law

For nn vectors: place them head-to-tail in sequence. The resultant is from the tail of the first to the head of the last.

Algebraic / Component Method

In components: R⃗=A⃗+B⃗=(Ax+Bx)i^+(Ay+By)j^.\vec{R} = \vec{A} + \vec{B} = (A_x + B_x)\hat{i} + (A_y + B_y)\hat{j}.

Magnitude: R=Rx2+Ry2.R = \sqrt{R_x^2 + R_y^2}.

Angle with xx-axis: tan⁡θ=Ry/Rx\tan\theta = R_y/R_x.

Properties

PropertyStatement
CommutativeA⃗+B⃗=B⃗+A⃗\vec{A} + \vec{B} = \vec{B} + \vec{A}
Associative(A⃗+B⃗)+C⃗=A⃗+(B⃗+C⃗)(\vec{A} + \vec{B}) + \vec{C} = \vec{A} + (\vec{B} + \vec{C})
IdentityA⃗+0⃗=A⃗\vec{A} + \vec{0} = \vec{A}
InverseA⃗+(−A⃗)=0⃗\vec{A} + (-\vec{A}) = \vec{0}

Maximum and Minimum

For two vectors of magnitudes AA and BB:

  • Maximum ∣R⃗∣=A+B|\vec{R}| = A + B (when parallel, θ=0\theta = 0).
  • Minimum ∣R⃗∣=∣A−B∣|\vec{R}| = |A - B| (when antiparallel, θ=180°\theta = 180°).

Worked Example

Q: A⃗=3i^+2j^\vec{A} = 3\hat{i} + 2\hat{j} and B⃗=−i^+4j^\vec{B} = -\hat{i} + 4\hat{j}. Find (a) R⃗=A⃗+B⃗\vec{R} = \vec{A} + \vec{B}, (b) magnitude and angle with xx-axis.

Solution: (a) R⃗=(3−1)i^+(2+4)j^=2i^+6j^\vec{R} = (3-1)\hat{i} + (2+4)\hat{j} = 2\hat{i} + 6\hat{j}.

(b) ∣R∣=4+36=40=210≈6.32|R| = \sqrt{4+36} = \sqrt{40} = 2\sqrt{10} \approx 6.32.

tan⁡θ=6/2=3⇒θ≈71.6°\tan\theta = 6/2 = 3 \Rightarrow \theta \approx 71.6°.

Q (using parallelogram law): Two forces of 5 N and 8 N act at 60° to each other. Find the resultant.

R=25+64+2(5)(8)cos⁡60°=89+40=129≈11.36 N.R = \sqrt{25 + 64 + 2(5)(8)\cos 60°} = \sqrt{89 + 40} = \sqrt{129} \approx 11.36\,\text{N}.

Angle with 5 N: tan⁡α=(8sin⁡60°)/(5+8cos⁡60°)=6.93/9≈0.77⇒α≈37.6°\tan\alpha = (8 \sin 60°)/(5 + 8\cos 60°) = 6.93/9 \approx 0.77 \Rightarrow \alpha \approx 37.6°.

Common Confusions

  • "Vectors add by simple arithmetic." — Only when parallel.
  • "Triangle law and parallelogram law give different answers." — They give the same answer; just different constructions.
  • Adding magnitudes (e.g., 5+8=135 + 8 = 13 N) is only correct for parallel vectors.

Key Takeaways

  • Graphical: triangle, parallelogram, polygon laws.
  • Algebraic: add components separately.
  • R=A2+B2+2ABcos⁡θR = \sqrt{A^2 + B^2 + 2AB\cos\theta} for two vectors.
  • Rmax⁡=A+BR_{\max} = A + B, Rmin⁡=∣A−B∣R_{\min} = |A - B|.
  • Vector addition is commutative and associative.

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