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Chapter 2: Units and Measurements

Physics is a quantitative science — every equation links measurable quantities. Before we can write equations sensibly, we must agree on what to measure, how to measure it, what units to use, and how to handle the inevitable errors in our measurements. This chapter develops the entire toolkit you will use in every subsequent chapter: the SI system, dimensional analysis (a remarkably powerful sanity-check), significant figures, and error propagation.

A famous failure illustrates why this matters: in 1999 NASA lost the Mars Climate Orbiter — a \125$ million spacecraft — because one team used pound-seconds and the other used newton-seconds. The probe burned up in Mars's atmosphere. Units are not bookkeeping; they are physics.

Key Concepts

2.1 Physical Quantities and Units

A physical quantity is anything that can be measured. Examples: length, mass, time, force, current, temperature.

A unit is a standardized reference amount of a physical quantity. To express a measurement we write: Q=nuQ = n \, u where nn is the numerical value and uu is the chosen unit. The same length 1.71.7 m can equally be written as 170170 cm or 0.00170.0017 km — but nun \, u is invariant: n1u1=n2u2n2=n1u1u2.n_1 u_1 = n_2 u_2 \quad \Longrightarrow \quad n_2 = n_1 \frac{u_1}{u_2}. Key consequence: if the unit is large, the numerical value is small, and vice versa. A car's mass is 10001000 kg, or equivalently 11 tonne — same physical quantity.

2.2 The International System of Units (SI)

The SI (Système International d'Unités), adopted in 1971 and refined since (most recently in 2019), uses seven base units from which all other units are derived.

Base quantityUnit nameSymbolModern definition (informal)
Lengthmetremdistance light travels in 1/2997924581/299792458 s
Masskilogramkgfixed via Planck's constant h=6.62607015×1034h = 6.626\,070\,15 \times 10^{-34} J s
Timeseconds91926317709\,192\,631\,770 periods of Cs-133 hyperfine transition
Electric currentampereAfixed via e=1.602176634×1019e = 1.602\,176\,634 \times 10^{-19} C
Thermodynamic temperaturekelvinKfixed via Boltzmann's constant kBk_B
Amount of substancemolemolNA=6.02214076×1023N_A = 6.022\,140\,76 \times 10^{23} entities
Luminous intensitycandelacdbased on 540540 THz radiation, 1/6831/683 W/sr

Two supplementary units complete the SI:

QuantityUnitSymbolDefinition
Plane angleradianradarc / radius
Solid anglesteradiansrarea / radius2^2

Derived units combine base units. A few you must know:

QuantityDerived SI unitIn base units
Forcenewton (N)kg m s2^{-2}
Energy / workjoule (J)kg m2^2 s2^{-2}
Powerwatt (W)kg m2^2 s3^{-3}
Pressurepascal (Pa)kg m1^{-1} s2^{-2}
Frequencyhertz (Hz)s1^{-1}
Chargecoulomb (C)A s
Potential differencevolt (V)kg m2^2 s3^{-3} A1^{-1}
Resistanceohm (Ω\Omega)kg m2^2 s3^{-3} A2^{-2}

Standard SI prefixes (memorise these — every chapter uses them):

MultiplePrefixSymbolSubmultiplePrefixSymbol
10110^{1}decada10110^{-1}decid
10210^{2}hectoh10210^{-2}centic
10310^{3}kilok10310^{-3}millim
10610^{6}megaM10610^{-6}microμ\mu
10910^{9}gigaG10910^{-9}nanon
101210^{12}teraT101210^{-12}picop
101510^{15}petaP101510^{-15}femtof
101810^{18}exaE101810^{-18}attoa

2.3 Measurement of Length, Mass and Time — Direct and Indirect

Length. Range of length measurements is enormous, from 1015\sim 10^{-15} m (proton) to 1026\sim 10^{26} m (observable universe).

  • Direct: metre scale (10310^{-3} m), vernier calipers (10410^{-4} m), screw gauge (10510^{-5} m).
  • Indirect: parallax method (astronomical distances), echo / RADAR / LIDAR (large terrestrial), electron microscopy (sub-micron).

Parallax method: to find the distance DD to a faraway star, observe it from two ends of Earth's orbit (basis b=2×1AUb = 2 \times 1\, \text{AU}). The parallax angle θ\theta (in radians) satisfies D=bθ.D = \frac{b}{\theta}.

Common astronomical length units:

  • 11 astronomical unit (AU) = 1.496×10111.496 \times 10^{11} m (mean Earth-Sun distance).
  • 11 light-year (ly) = 9.46×10159.46 \times 10^{15} m.
  • 11 parsec (pc) = 3.08×10163.08 \times 10^{16} m 3.26\approx 3.26 ly. (Distance at which 11 AU subtends 11 arc-second.)

Mass. From 1030\sim 10^{-30} kg (electron) to 1053\sim 10^{53} kg (universe).

  • Direct: common / beam / electronic balance.
  • Indirect: gravitational / inertial methods. Mass of Earth from gg and the law of gravitation; mass of a planet from a satellite's orbit; atomic masses by mass spectrometer.
  • 11 atomic mass unit (u) = 1.66×10271.66 \times 10^{-27} kg, defined as 1/121/12 of the mass of 12^{12}C.

Time. From 1024\sim 10^{-24} s (nuclear) to 1017\sim 10^{17} s (age of universe).

  • Atomic clocks (Cs-133): accurate to 11 part in 101310^{13} — drift of about 11 s in 300000300\,000 years.
  • Optical / strontium lattice clocks: 11 part in 101810^{18} (research).

2.4 Accuracy, Precision and Errors

  • Accuracy: closeness to the true value.
  • Precision: closeness of repeated measurements to each other (i.e., reproducibility).

A rifle that always hits the same spot but not the bullseye is precise but inaccurate; one whose shots scatter around the bullseye is accurate on average but imprecise.

Sources of error:

  • Systematic errors — repeatable bias due to instrument zero-error, calibration drift, environmental conditions, or experimenter's habit. Reduced by correcting / recalibrating, not by averaging.
  • Random errors — unpredictable fluctuations from many small unknown causes. Reduced by taking many readings and averaging.
  • Gross errors / blunders — recording, arithmetic, or instrument-reading mistakes. Removed by repeating the measurement.
  • Least-count error — limit of the resolution of the instrument; treated like a random error.

2.5 Absolute, Relative and Percentage Errors

Suppose a quantity aa is measured nn times, giving readings a1,a2,,ana_1, a_2, \ldots, a_n. The arithmetic mean is taken as the best estimate of the true value: aˉ=1ni=1nai.\bar{a} = \frac{1}{n} \sum_{i=1}^{n} a_i.

  • Absolute error of the ii-th reading: Δai=aˉai\Delta a_i = \vert \bar{a} - a_i\vert .
  • Mean absolute error: Δaˉ=1ni=1nΔai\Delta \bar{a} = \dfrac{1}{n} \sum_{i=1}^{n} \Delta a_i.
  • Relative error: δa=Δaˉaˉ\delta a = \dfrac{\Delta \bar{a}}{\bar{a}} (dimensionless).
  • Percentage error: δa×100%\delta a \times 100 \%.

The final result is reported as a=aˉ±Δaˉ.a = \bar{a} \pm \Delta \bar{a}.

2.6 Propagation of Errors (Combinations)

If A=aˉ±ΔaA = \bar{a} \pm \Delta a and B=bˉ±ΔbB = \bar{b} \pm \Delta b, then for various combinations the errors add as follows:

(a) Sum or difference. Z=A+BZ = A + B or Z=ABZ = A - B. The absolute errors add: ΔZ=ΔA+ΔB.\Delta Z = \Delta A + \Delta B.

(b) Product or quotient. Z=ABZ = A B or Z=A/BZ = A / B. The relative errors add: ΔZZ=ΔAA+ΔBB.\frac{\Delta Z}{Z} = \frac{\Delta A}{A} + \frac{\Delta B}{B}.

(c) Power. Z=ApBq/CrZ = A^p B^q / C^r. The relative errors multiply by the exponents and add: ΔZZ=pΔAA+qΔBB+rΔCC.\frac{\Delta Z}{Z} = |p| \frac{\Delta A}{A} + |q| \frac{\Delta B}{B} + |r| \frac{\Delta C}{C}.

Important: errors always add (never subtract) when propagating, because we assume the worst case. This is why subtraction of nearly equal quantities is dangerous: the absolute error stays the same but the result shrinks, so the relative error blows up. Always design experiments to avoid taking the difference of two nearly equal large numbers.

Derivation sketch for the product rule. Take logarithms: lnZ=lnA+lnB\ln Z = \ln A + \ln B. Differentiating: dZ/Z=dA/A+dB/BdZ/Z = dA/A + dB/B. Replacing differentials by errors and adding magnitudes gives the rule.

2.7 Significant Figures

The significant figures of a measurement are the digits known reliably plus the first uncertain digit.

Examples: 1.231.23 has 3 s.f.; 1.2301.230 has 4 s.f. (trailing zero after the decimal matters); 12301230 has 33 or 44 s.f. (ambiguous — write 1.23×1031.23 \times 10^3 or 1.230×1031.230 \times 10^3).

Rules for counting significant figures:

  1. All non-zero digits are significant. (34563456 has 4 s.f.)
  2. Zeros between non-zero digits are significant. (30053005 has 4 s.f.)
  3. Leading zeros are NOT significant. (0.00340.0034 has 2 s.f.)
  4. Trailing zeros after a decimal are significant. (3.4003.400 has 4 s.f.)
  5. Trailing zeros in a whole number without a decimal point are ambiguous. Express in scientific notation. (45004500 may be 2, 3, or 4 s.f.)
  6. Exact / counting numbers (N=23N = 23 students, π\pi, 22 in E=12mv2E = \frac{1}{2}mv^2) have infinite significant figures.

Rules for arithmetic with s.f.:

  • Addition / subtraction — the result has the same number of decimal places as the operand with the fewest decimal places. Example: 2.34+0.012=2.352.34 + 0.012 = 2.35 (2 d.p., dropped to least).
  • Multiplication / division — the result has the same number of significant figures as the operand with the fewest s.f. Example: 5.74×0.4=25.74 \times 0.4 = 2 (1 s.f.).
  • Rounding off: if the digit to be dropped is
    • less than 55 — drop it (round down);
    • greater than 55 — round up;
    • exactly 55 — round to even (banker's rounding): 1.251.21.25 \to 1.2 but 1.351.41.35 \to 1.4.

2.8 Dimensions of Physical Quantities

The dimension of a physical quantity is the way it depends on the seven base quantities. The base quantities are denoted:

[L] length,[M] mass,[T] time,[A] current,[K] temperature,[mol],[cd].\text{[L] length}, \quad \text{[M] mass}, \quad \text{[T] time}, \quad \text{[A] current}, \quad \text{[K] temperature}, \quad \text{[mol]}, \quad \text{[cd]}.

For mechanics, only L, M, T\text{L, M, T} usually matter.

Dimensional formula of a quantity expresses it as [MaLbTc][\text{M}^a \text{L}^b \text{T}^c].

Examples:

QuantityFormulaDimensional formula
AreaL×LL \times L[M0L2T0][\text{M}^0 \text{L}^2 \text{T}^0]
VolumeL3L^3[M0L3T0][\text{M}^0 \text{L}^3 \text{T}^0]
DensityM/VM / V[M1L3T0][\text{M}^1 \text{L}^{-3} \text{T}^0]
VelocityL/TL / T[M0L1T1][\text{M}^0 \text{L}^1 \text{T}^{-1}]
AccelerationL/T2L / T^2[M0L1T2][\text{M}^0 \text{L}^1 \text{T}^{-2}]
ForceMaM a[M1L1T2][\text{M}^1 \text{L}^1 \text{T}^{-2}]
PressureF/AF / A[M1L1T2][\text{M}^1 \text{L}^{-1} \text{T}^{-2}]
Energy / workFsF \cdot s[M1L2T2][\text{M}^1 \text{L}^2 \text{T}^{-2}]
PowerW/tW / t[M1L2T3][\text{M}^1 \text{L}^2 \text{T}^{-3}]
Momentummvm v[M1L1T1][\text{M}^1 \text{L}^1 \text{T}^{-1}]
ImpulseFtF \cdot t[M1L1T1][\text{M}^1 \text{L}^1 \text{T}^{-1}] (same as momentum)
Frequency1/T1/T[M0L0T1][\text{M}^0 \text{L}^0 \text{T}^{-1}]
Angular velocityθ/t\theta/t[M0L0T1][\text{M}^0 \text{L}^0 \text{T}^{-1}]
Gravitational constant GGFr2/m1m2Fr^2/m_1m_2[M1L3T2][\text{M}^{-1} \text{L}^3 \text{T}^{-2}]
Planck constant hhE/νE/\nu[M1L2T1][\text{M}^1 \text{L}^2 \text{T}^{-1}]
Electric chargeItIt[A1T1][\text{A}^1 \text{T}^1]
Electric fieldF/qF/q[M1L1T3A1][\text{M}^1 \text{L}^1 \text{T}^{-3} \text{A}^{-1}]

Dimensionless quantities: angle (θ\theta), strain, refractive index, relative density, π\pi, exponents, trigonometric values, logarithms — all carry [M0L0T0][\text{M}^0 \text{L}^0 \text{T}^0].

2.9 Principle of Homogeneity (Dimensional Consistency)

Every term in a physically valid equation must have the same dimensions.

You cannot add quantities of different dimensions, just as you cannot add metres to seconds. This single rule is the engine behind dimensional analysis.

Use 1 — Checking equations. Take s=ut+12at2s = ut + \tfrac{1}{2} a t^2.

  • [s]=L[s] = \text{L}.
  • [ut]=(L T1)(T)=L[ut] = (\text{L T}^{-1})(\text{T}) = \text{L}. \checkmark
  • [at2]=(L T2)(T2)=L[at^2] = (\text{L T}^{-2})(\text{T}^2) = \text{L}. \checkmark All terms agree — the equation is dimensionally consistent. (Dimensional consistency does not prove correctness; it only rules out gross errors.)

Use 2 — Converting units. Convert 11 joule into ergs. [J]=[M L2T2][\text{J}] = [\text{M L}^2 \text{T}^{-2}]. SI: kg, m, s. CGS: g, cm, s. 1J=(1kg)(1m)2(1s)2=(103g)(102cm)2(1s)2=103×104g cm2s2=107erg.1\, \text{J} = (1\, \text{kg})(1\, \text{m})^2 (1\, \text{s})^{-2} = (10^3\, \text{g})(10^2\, \text{cm})^2 (1\, \text{s})^{-2} = 10^3 \times 10^4\, \text{g cm}^2 \text{s}^{-2} = 10^7\, \text{erg}.

Use 3 — Deriving relationships. Suppose the period TT of a simple pendulum depends only on its length ll, mass mm, and gravitational acceleration gg. Write T=klambgcT = k\, l^a m^b g^c with kk a dimensionless constant. Equating dimensions: T1=(L)a(M)b(L T2)c=MbLa+cT2c.\text{T}^1 = (\text{L})^a (\text{M})^b (\text{L T}^{-2})^c = \text{M}^b \text{L}^{a+c} \text{T}^{-2c}. Comparing: b=0b = 0, a+c=0a + c = 0, 2c=1c=1/2-2c = 1 \Rightarrow c = -1/2, a=1/2a = 1/2. Hence T=kl/g.T = k \sqrt{l/g}. Dimensional analysis cannot find k=2πk = 2\pi — but it has correctly predicted that the period is independent of mass, an experimental fact.

2.10 Limitations of Dimensional Analysis

Dimensional analysis is powerful but not all-powerful:

  1. Cannot determine dimensionless constants (the 2π2\pi in the pendulum, the 12\tfrac{1}{2} in 12mv2\tfrac{1}{2} m v^2).
  2. Fails when a quantity depends on more than three M, L, T variables — you don't have enough equations.
  3. Fails for trigonometric, exponential, or logarithmic relations (e.g. y=Asin(ωt)y = A \sin(\omega t) — sin is dimensionless, no help in determining AA).
  4. Cannot decide between s=ut+12at2s = ut + \tfrac{1}{2} at^2 and s=ut+at2s = ut + at^2 — both are dimensionally consistent. Other physics is needed.
  5. Cannot distinguish two quantities with identical dimensions — e.g., torque and energy both [M L2T2][\text{M L}^2 \text{T}^{-2}]; impulse and momentum both [M L T1][\text{M L T}^{-1}].

2.11 Order-of-Magnitude Estimation

A quantity aa written as a=b×10na = b \times 10^n with 0.5b<50.5 \le b < 5 is said to have order of magnitude 10n10^n. (Some books use 1b<101 \le b < 10.) Order-of-magnitude reasoning lets you check whether an answer is reasonable: if you compute the mass of an electron and get 10310^{-3} kg, you have made a 27-orders-of-magnitude error.

Worked Examples

Example 2.1 — Convert units using dimensions. The value of GG in SI is 6.67×10116.67 \times 10^{-11} N m2^2/kg2^2. Find its value in CGS (dyne cm2^2/g2^2).

Solution. [G]=[M1L3T2][G] = [\text{M}^{-1} \text{L}^3 \text{T}^{-2}]. The conversion factor from SI to CGS for GG is: (kgg)1(mcm)3(ss)2=(103)1(102)3(1)2=103×106=103.\left(\frac{\text{kg}}{\text{g}}\right)^{-1} \left(\frac{\text{m}}{\text{cm}}\right)^{3} \left(\frac{\text{s}}{\text{s}}\right)^{-2} = (10^3)^{-1} (10^2)^3 (1)^{-2} = 10^{-3} \times 10^6 = 10^3. Hence GCGS=6.67×1011×103=6.67×108G_{\text{CGS}} = 6.67 \times 10^{-11} \times 10^3 = 6.67 \times 10^{-8} dyne cm2^2/g2^2.

Example 2.2 — Significant figures arithmetic. A rectangular sheet has length 16.216.2 cm and breadth 10.110.1 cm. Compute its area, reporting to the correct number of significant figures.

Solution. 16.2×10.1=163.6216.2 \times 10.1 = 163.62 cm2^2. Both operands have 3 s.f., so the answer must have 3 s.f.: A=164A = 164 cm2^2.

Example 2.3 — Error in a formula. The period of a pendulum is determined from T=2πl/gT = 2\pi\sqrt{l/g}. The length is measured as l=100.0±0.1l = 100.0 \pm 0.1 cm and the time for 2020 oscillations is 40.2±0.140.2 \pm 0.1 s. Find the percentage error in gg.

Solution. From T=2πl/gT = 2\pi\sqrt{l/g}, we get g=4π2l/T2g = 4\pi^2 l / T^2. Hence Δgg=Δll+2ΔTT.\frac{\Delta g}{g} = \frac{\Delta l}{l} + 2\frac{\Delta T}{T}. Δl/l=0.1/100=0.001=0.1%\Delta l / l = 0.1 / 100 = 0.001 = 0.1\%. T=40.2/20=2.01T = 40.2/20 = 2.01 s, ΔT=0.1/20=0.005\Delta T = 0.1/20 = 0.005 s, ΔT/T=0.005/2.01=0.249%\Delta T / T = 0.005/2.01 = 0.249\%. Δg/g=0.1%+2×0.249%=0.6%\Delta g / g = 0.1\% + 2 \times 0.249\% = 0.6\% (approximately).

Lesson: the time error contributes much more than the length error, because (a) it enters with a factor of 2 (squared dependence) and (b) it is intrinsically larger. To improve, count more oscillations.

Example 2.4 — Dimensional analysis to derive a formula. The drag force FF on a sphere moving slowly through a viscous fluid depends on the radius rr, the viscosity η\eta (units kg m1^{-1} s1^{-1}) and the velocity vv. Derive the form of the dependence.

Solution. Assume F=kraηbvcF = k\, r^a \eta^b v^c. Equating dimensions: [M L T2]=(L)a(M L1T1)b(L T1)c=MbLab+cTbc.[\text{M L T}^{-2}] = (\text{L})^a (\text{M L}^{-1} \text{T}^{-1})^b (\text{L T}^{-1})^c = \text{M}^b \text{L}^{a-b+c} \text{T}^{-b-c}. b=1b = 1, bc=2c=1-b - c = -2 \Rightarrow c = 1, ab+c=1a=1a - b + c = 1 \Rightarrow a = 1. So F=kηrvF = k \eta r v. (Stokes' law gives k=6πk = 6\pi.)

Example 2.5 — Mean and error. Five measurements of a time period give 2.63,2.56,2.42,2.71,2.802.63, 2.56, 2.42, 2.71, 2.80 s. Find the mean, the mean absolute error, the relative error and the percentage error.

Solution. Mean Tˉ=(2.63+2.56+2.42+2.71+2.80)/5=13.12/5=2.624\bar{T} = (2.63+2.56+2.42+2.71+2.80)/5 = 13.12/5 = 2.624 s. Absolute errors: 0.006,0.064,0.204,0.086,0.176\vert 0.006\vert , \vert 0.064\vert , \vert 0.204\vert , \vert 0.086\vert , \vert 0.176\vert — i.e., 0.006,0.064,0.204,0.086,0.1760.006, 0.064, 0.204, 0.086, 0.176. Mean absolute error: (0.006+0.064+0.204+0.086+0.176)/5=0.536/5=0.1070.11(0.006+0.064+0.204+0.086+0.176)/5 = 0.536/5 = 0.107 \approx 0.11 s. Relative error: 0.11/2.62=0.0420.11/2.62 = 0.042. Percentage error: 4.2%4.2\%. Reported: T=(2.62±0.11)T = (2.62 \pm 0.11) s, or T=2.62T = 2.62 s ±4.2%\pm 4.2\%.

Example 2.6 — Order of magnitude. Estimate the order of magnitude of the mass of air in a 1010 m ×10\times 10 m ×3\times 3 m room. (ρair1.2\rho_{\text{air}} \approx 1.2 kg/m3^3.)

Solution. V=300V = 300 m3^3, m=ρV=1.2×300=360m = \rho V = 1.2 \times 300 = 360 kg. Order of magnitude 10210^2 kg.

Common Traps

  • "Light-year is a unit of time." It is a unit of length (distance light travels in one year, 9.46×10159.46 \times 10^{15} m).
  • "AU = atomic unit of mass." No: AU = astronomical unit of length. Atomic mass unit is u.
  • "Subtraction reduces error." Wrong. Errors in ABA - B are ΔA+ΔB\Delta A + \Delta B — they add. Worse, the value ABA-B may be small, so the relative error explodes.
  • In powers, exponent in error formula is taken with absolute value. Even for negative powers — ΔZ/Z=pΔA/A\Delta Z / Z = \vert p\vert \, \Delta A / A, never with a minus sign.
  • Ignoring the 22 when the formula contains T2T^2 or r2r^2. Errors propagate through exponents.
  • Mixing decimal places and significant figures rules. Add/subtract uses decimal places. Multiply/divide uses significant figures.
  • Treating trailing zeros without a decimal as significant. 45004500 is ambiguous; write 4.5×1034.5 \times 10^3 (2 s.f.) or 4.500×1034.500 \times 10^3 (4 s.f.).
  • "Dimensional analysis proves a formula correct." It only proves dimensional consistency — necessary, not sufficient.
  • Forgetting that angle is dimensionless. [θ]=[M0L0T0][\theta] = [\text{M}^0 \text{L}^0 \text{T}^0] — even though it has the unit radian.
  • Confusing the dimensions of torque and energy. Both are [M L2T2][\text{M L}^2 \text{T}^{-2}], but torque is a vector and energy a scalar. The two are physically very different.
  • Ignoring the difference between accuracy and precision. Repeating a faulty thermometer's reading 10001000 times gives high precision but the same systematic inaccuracy.
  • Using g=9.8g = 9.8 m/s2^2 to 3 s.f. but then quoting an answer to 6 s.f. A result is no more precise than its least-precise input.

Quick Recap

  • SI has 7 base units (m, kg, s, A, K, mol, cd) + 2 supplementary (rad, sr).
  • Modern SI definitions (post-2019) are anchored to fundamental constants (c,h,e,kB,NAc, h, e, k_B, N_A).
  • Important indirect length techniques: parallax (astronomy), echo / RADAR (terrestrial).
  • Accuracyprecision. Errors are systematic (correctable) or random (averaged out).
  • For a series of nn measurements, the best estimate is the mean; the spread is captured by the mean absolute error.
  • Error propagation:
    • Sum / difference: absolute errors add.
    • Product / quotient: relative errors add.
    • Powers: relative errors multiply by exponent and add.
  • Significant figures:
    • Add/sub \to decimal-place rule.
    • Mul/div \to s.f. rule.
  • Dimensional formula uses [MaLbTc][\text{M}^a \text{L}^b \text{T}^c]. The principle of homogeneity says every term has the same dimensions.
  • Three classical uses of dimensions: checking equations, converting units, guessing formulas (up to a dimensionless constant).
  • Dimensional analysis fails for dimensionless multipliers, for trig/exp/log, and for >3> 3 unknowns.

Formula Summary

ConceptFormulaNotes
Unit conversionn1u1=n2u2n_1 u_1 = n_2 u_2invariance of measurement
ParallaxD=b/θD = b / \thetaθ\theta in radians
Meanaˉ=1nai\bar{a} = \tfrac{1}{n}\sum a_ibest estimate
Mean absolute errorΔaˉ=1naˉai\Delta\bar{a} = \tfrac{1}{n}\sum \lvert\bar{a} - a_i\rvertscatter measure
Relative / percentage errorΔaˉ/aˉ\Delta\bar{a}/\bar{a}; ×100%\times 100\%dimensionless
Error in A±BA \pm BΔZ=ΔA+ΔB\Delta Z = \Delta A + \Delta Babsolute errors add
Error in ABA B or A/BA/BΔZ/Z=ΔA/A+ΔB/B\Delta Z/Z = \Delta A/A + \Delta B/Brelative errors add
Error in ApBq/CrA^p B^q / C^rΔZ/Z=pΔA/A+qΔB/B+rΔC/C\Delta Z/Z = \lvert p\rvert\Delta A/A + \lvert q\rvert\Delta B/B + \lvert r\rvert\Delta C/Cwith abs of exponents
Pendulum periodT=2πl/gT = 2\pi\sqrt{l/g}independent of mass
Stokes' lawF=6πηrvF = 6\pi\eta r vviscous drag on sphere
Joule-erg conversion1J=107erg1\, \text{J} = 10^7\, \text{erg}from dimensional conversion

With this measurement toolkit in hand, the next chapter dives into the first real physics problem: describing the motion of a particle along a straight line.

Sub-topics

8 pages
Quiz
Units and Measurements
15 questions · pick the best answer
Q1

Which of the following is NOT an SI base unit?

Q2

The dimensional formula of pressure is:

Q3

Which pair has the SAME dimensional formula?

Q4

How many significant figures are in the number 0.003400?

Q5

A student measures the side of a square plate as 3.5 cm. The area to the correct number of significant figures is:

Q6

If the percentage errors in length, breadth and height of a cuboid are 1%, 2% and 3%, the percentage error in its volume is:

Q7

The period of a pendulum is T = 2π√(l/g). Percentage error in g is best computed as:

Q8

One light-year is approximately:

Q9

Which of the following is a dimensionless quantity?

Q10

The dimensional formula of the gravitational constant G is:

Q11

Which limitation of dimensional analysis is illustrated by the formulas s = ut + ½at² and s = ut + at² being both dimensionally valid?

Q12

The value of 1 joule in ergs is:

Q13

Five measurements give 1.20, 1.22, 1.25, 1.19, 1.24 m. The mean absolute error is closest to:

Q14

An instrument that gives the same reading every time but a value different from the true value is:

Q15

The radius of a sphere is measured as (3.0 ± 0.1) cm. The maximum percentage error in its volume V = (4/3)πr³ is: