← Back to Play
Inclined Plane Lab
Class XI · Laws of Motion: friction & angle of repose.
Net F‖
0.00 N
a
0.00 m/s²
Status
Static
θ_repose
21.8°
Controls
Angle θ (°)
Mass m (kg)
μ_s (static)
μ_k (kinetic)
Applied F (N, +up slope)
g (m/s²)
Formulas
- N = mg cos θ
- mg sinθ vs f = μN
- θ_repose = tan⁻¹(μ_s)
- a = (mg sinθ − μ_k mg cosθ) / m
Try this
Set μ_s = 0.5. Slowly raise θ. The block starts slipping right when θ ≈ tan⁻¹(0.5) ≈ 26.6°. Now lower μ_k below μ_s: the slide accelerates further once it begins.