Physics Lab

Unit 11: Magnetism, EMI, AC and EM Waves

A heavyweight unit: 3–4 MCQs in NEET. It combines magnetism (Biot-Savart, Ampere's law, force on currents) with electromagnetic induction, AC circuits (LCR, resonance, transformer), and the brief topic of EM waves. Questions mix conceptual (rule applications, direction of induced current) with formula-recall (RMS values, resonance frequency, transformer ratio).

Concept Map

  • Magnetic field of currents — Biot-Savart, Ampere's law (straight wire, loop, solenoid, toroid)
  • Lorentz force, motion of charge in B, cyclotron
  • Force on current-carrying wire, force between parallel wires, torque on loop, galvanometer (A, V)
  • Magnetism and matter — dia/para/ferro, susceptibility, hysteresis
  • EMI — Faraday, Lenz, motional EMF, self/mutual inductance
  • AC — RMS, R/L/C alone, LCR, resonance, power factor, transformer
  • EM waves — Maxwell brief, c=1/μ0ε0c = 1/\sqrt{\mu_0\varepsilon_0}, spectrum

Topic 1: Magnetic Field due to Currents

Sub-topic A: Biot-Savart Law

dB=μ04πId×r^r2,d\vec B = \frac{\mu_0}{4\pi}\,\frac{I\,d\vec\ell \times \hat r}{r^2},

with μ0=4π×107 T m/A\mu_0 = 4\pi \times 10^{-7}\ \text{T m/A}.

Sub-topic B: Field of a Straight Wire

For a finite straight wire, field at perpendicular distance aa:

B=μ0I4πa(sinθ1+sinθ2).B = \frac{\mu_0 I}{4\pi a}(\sin\theta_1 + \sin\theta_2).

For infinitely long wire: θ1=θ2=90°\theta_1 = \theta_2 = 90°,

B=μ0I2πa.B = \frac{\mu_0 I}{2\pi a}.

Direction by right-hand rule (curl of fingers along BB, thumb along II).

Sub-topic C: Field of a Circular Loop

At centre of a loop of radius RR carrying current II:

B=μ0I2R.B = \frac{\mu_0 I}{2 R}.

For NN turns: B=μ0NI/(2R)B = \mu_0 N I/(2R).

On axis at distance xx:

Baxis=μ0IR22(R2+x2)3/2.B_\text{axis} = \frac{\mu_0 I R^2}{2(R^2 + x^2)^{3/2}}.

At large distance, Bμ0IR2/(2x3)=μ0m/(2πx3)B \approx \mu_0 I R^2/(2 x^3) = \mu_0 m/(2\pi x^3) where m=IA=IπR2m = I A = I\pi R^2 is the magnetic moment.

Sub-topic D: Ampere's Law

Bd=μ0Ienc.\oint \vec B \cdot d\vec\ell = \mu_0 I_\text{enc}.

Use Amperian loops to find BB for symmetric currents:

  • Long solenoid (n turns per unit length): B=μ0nIB = \mu_0 n I inside, B0B \approx 0 outside.
  • Toroid of NN turns at mean radius rr: B=μ0NI/(2πr)B = \mu_0 N I/(2\pi r).

Topic 2: Lorentz Force and Motion in B

Sub-topic A: Lorentz Force

F=q(E+v×B).\vec F = q(\vec E + \vec v \times \vec B).

The magnetic part does no work (Fv\vec F \perp \vec v).

Sub-topic B: Charged Particle in Uniform B

If vB\vec v \perp \vec B: circular motion of radius

r=mvqB,T=2πmqB.r = \frac{mv}{qB}, \quad T = \frac{2\pi m}{qB}.

The period is independent of speed — basis of cyclotron.

If v\vec v has component along B\vec B: helical motion. Pitch p=vTp = v_\parallel T.

Sub-topic C: Cyclotron

Particle accelerated by alternating voltage between dees, magnetically curved. Cyclotron frequency fc=qB/(2πm)f_c = qB/(2\pi m). Max KE:

Kmax=q2B2R22m.K_\text{max} = \frac{q^2 B^2 R^2}{2m}.

Relativistic limit: at high speed mass increases, cyclotron period changes — formula breaks down.

Topic 3: Force on Currents

Sub-topic A: Force on a Current Wire

F=IL×B,F=BILsinθ.\vec F = I \vec L \times \vec B, \quad F = BIL\sin\theta.

Sub-topic B: Two Parallel Wires

Force per unit length between two long parallel wires carrying I1,I2I_1, I_2, separated by dd:

F/L=μ0I1I22πd.F/L = \frac{\mu_0 I_1 I_2}{2\pi d}.

Attractive if currents are parallel; repulsive if antiparallel. (This defines the ampere.)

Sub-topic C: Torque on a Current Loop

A loop of NN turns, area AA, carrying current II in field BB has magnetic moment m=NIAm = NIA. Torque:

τ=m×B,τ=NIABsinθ.\vec\tau = \vec m \times \vec B, \quad \tau = NIAB\sin\theta.

PE: U=mBU = -\vec m \cdot \vec B.

Sub-topic D: Moving-Coil Galvanometer

Deflection ϕ=(NAB/k)I\phi = (NAB/k)I, where kk is restoring torsion constant. Current sensitivity: ϕ/I=NAB/k\phi/I = NAB/k. Voltage sensitivity: ϕ/V=NAB/(kRg)\phi/V = NAB/(kR_g).

Ammeter: galvanometer in parallel with a low shunt S=GIg/(IIg)S = G I_g/(I - I_g).

Voltmeter: galvanometer in series with a high R=V/IgGR = V/I_g - G.

Topic 4: Magnetism and Matter

Sub-topic A: Magnetic Susceptibility and Permeability

M=χH,B=μ0(H+M)=μ0(1+χ)H=μH.M = \chi H, \quad B = \mu_0(H + M) = \mu_0(1 + \chi)H = \mu H.

Relative permeability μr=1+χ\mu_r = 1 + \chi.

Sub-topic B: Types of Materials

Typeχ\chiμr\mu_rExamples
Diamagneticsmall, -slightly <1< 1Bi, Cu, water
Paramagneticsmall, ++slightly >1>1Al, Pt, O₂
Ferromagneticlarge, ++1\gg 1Fe, Ni, Co

Above the Curie temperature, ferromagnet becomes paramagnet.

Sub-topic C: Hysteresis

The BB-HH curve for a ferromagnet is a closed loop. Key points: residual magnetism (retentivity), coercivity (the HH to demagnetize). Area = energy dissipated per cycle.

  • Soft iron: low retentivity, low coercivity → electromagnets, transformer cores.
  • Steel: high retentivity, high coercivity → permanent magnets.

Topic 5: Electromagnetic Induction

Sub-topic A: Faraday's Law

EMF induced in a closed loop = rate of change of flux:

ε=dΦBdt,ΦB=BdA.\varepsilon = -\frac{d\Phi_B}{dt}, \quad \Phi_B = \int \vec B \cdot d\vec A.

For NN turns: ε=NdΦB/dt\varepsilon = -N\,d\Phi_B/dt.

Sub-topic B: Lenz's Law

The direction of the induced current is such that it opposes the change that produces it (conservation of energy).

Sub-topic C: Motional EMF

A rod of length LL moving with velocity vv in field BB (all mutually perpendicular):

ε=BLv.\varepsilon = BLv.

If the rod is part of a circuit of resistance RR: induced current I=BLv/RI = BLv/R; retarding force F=BIL=B2L2v/RF = BIL = B^2 L^2 v/R; power dissipated P=B2L2v2/R=FvP = B^2L^2v^2/R = Fv.

Sub-topic D: Self-Inductance

Φ=LI,ε=LdI/dt.\Phi = L I, \quad \varepsilon = -L\,dI/dt.

For long solenoid: L=μ0n2AL = \mu_0 n^2 A \ell.

Energy stored: U=12LI2U = \tfrac{1}{2} L I^2. Energy density: u=B2/(2μ0)u = B^2/(2\mu_0).

Sub-topic E: Mutual Inductance

ε2=MdI1/dt.\varepsilon_2 = -M\,dI_1/dt.

For two coaxial solenoids: M=μ0n1n2AM = \mu_0 n_1 n_2 A \ell.

Topic 6: Alternating Current

Sub-topic A: AC Voltage and Current

V(t)=V0sinωtV(t) = V_0\sin\omega t, I(t)=I0sin(ωtϕ)I(t) = I_0\sin(\omega t - \phi).

  • Peak value: V0V_0.
  • RMS value: Vrms=V0/2V_\text{rms} = V_0/\sqrt{2}. Similarly Irms=I0/2I_\text{rms} = I_0/\sqrt{2}.
  • Average over half cycle: Vavg=2V0/πV_\text{avg} = 2V_0/\pi.

Sub-topic B: Single-Element Circuits

ElementVoltage-Current relationReactancePhase
Resistor RV=IRV = IRRRVV in phase with II
Inductor LV=LdI/dtV = L\,dI/dtXL=ωLX_L = \omega LVV leads II by π/2\pi/2
Capacitor CI=CdV/dtI = C\,dV/dtXC=1/(ωC)X_C = 1/(\omega C)VV lags II by π/2\pi/2

Sub-topic C: Series LCR Circuit

Impedance:

Z=R2+(XLXC)2.Z = \sqrt{R^2 + (X_L - X_C)^2}.

Current amplitude I0=V0/ZI_0 = V_0/Z.

Phase tanϕ=(XLXC)/R\tan\phi = (X_L - X_C)/R.

Average power:

Pˉ=VrmsIrmscosϕ=Irms2R.\bar P = V_\text{rms} I_\text{rms} \cos\phi = I_\text{rms}^2 R.

cosϕ\cos\phi is the power factor. For pure L or pure C, cosϕ=0\cos\phi = 0 → no average power dissipated (wattless current).

Sub-topic D: Resonance

Series LCR resonates when XL=XCX_L = X_C:

ω0=1/LC,f0=1/(2πLC).\omega_0 = 1/\sqrt{LC}, \quad f_0 = 1/(2\pi\sqrt{LC}).

At resonance: Z=RZ = R (minimum), I0=V0/RI_0 = V_0/R (maximum), cosϕ=1\cos\phi = 1.

Quality factor:

Q=ω0L/R=1/(ω0RC).Q = \omega_0 L/R = 1/(\omega_0 R C).

High Q → sharp resonance, narrow bandwidth.

Sub-topic E: Transformer

Ideal transformer: Vp/Vs=Np/NsV_p/V_s = N_p/N_s and Ip/Is=Ns/NpI_p/I_s = N_s/N_p. Step-up: Ns>NpN_s > N_p, Vs>VpV_s > V_p but Is<IpI_s < I_p.

Efficiency η=Ps/Pp\eta = P_s/P_p. Losses: copper (I²R), iron (hysteresis + eddy current), flux leakage.

Topic 7: Electromagnetic Waves

Sub-topic A: Displacement Current

Maxwell added the displacement current Id=ε0dΦE/dtI_d = \varepsilon_0\,d\Phi_E/dt to make Ampere's law consistent. So

Bd=μ0(Ic+Id).\oint \vec B \cdot d\vec\ell = \mu_0 (I_c + I_d).

Sub-topic B: Maxwell's Equations (qualitative)

Four equations: Gauss for E, Gauss for B (no monopoles), Faraday's law, Ampere-Maxwell. They predict EM waves.

Sub-topic C: Properties of EM Waves

  • Transverse: EBk\vec E \perp \vec B \perp \vec k (propagation direction).
  • Speed in vacuum: c=1/μ0ε03×108c = 1/\sqrt{\mu_0\varepsilon_0} \approx 3 \times 10^8 m/s.
  • In a medium: v=1/με=c/nv = 1/\sqrt{\mu\varepsilon} = c/n.
  • E0/B0=cE_0/B_0 = c.
  • Energy density: u=12ε0E2+B2/(2μ0)u = \tfrac{1}{2}\varepsilon_0 E^2 + B^2/(2\mu_0). For sinusoidal wave, average u=12ε0E02u = \tfrac{1}{2}\varepsilon_0 E_0^2.
  • Intensity (Poynting): S=EB/μ0=ucS = E B/\mu_0 = u c.
  • Carry momentum: p=E/cp = E/c per photon; produce radiation pressure P=I/cP = I/c (absorbed) or 2I/c2I/c (reflected).

Sub-topic D: EM Spectrum (Memorise order)

Regionλ\lambda rangeSource
Radio waves>0.1 m> 0.1\ \text{m}LC oscillators, antennas
Microwaves1 mm1\ \text{mm}0.1 m0.1\ \text{m}Klystron, magnetron
Infrared700 nm700\ \text{nm}1 mm1\ \text{mm}Hot bodies
Visible400 nm400\ \text{nm}700 nm700\ \text{nm}Atomic transitions
Ultraviolet1 nm1\ \text{nm}400 nm400\ \text{nm}Sun, arcs
X-rays0.01 nm0.01\ \text{nm}10 nm10\ \text{nm}Stopping fast electrons
Gamma rays<0.01 nm< 0.01\ \text{nm}Nuclear transitions

Visible (mnemonic VIBGYOR): violet (\sim 400 nm) → red (\sim 700 nm).

NEET Pattern MCQ Tips

  • Biot-Savart: BB at centre of loop or straight wire — direct plug-in.
  • Ampere's law: solenoid and toroid.
  • Charged particle in B: r=mv/(qB)r = mv/(qB), TT independent of vv.
  • Force on parallel wires: attractive if same direction.
  • Torque on loop: τ=NIABsinθ\tau = NIAB\sin\theta.
  • Lenz's law: direction of induced current.
  • Motional EMF: ε=BLv\varepsilon = BLv.
  • Inductor stored energy: 12LI2\tfrac{1}{2}LI^2.
  • AC: RMS = peak/2\sqrt{2}.
  • LCR resonance: ω0=1/LC\omega_0 = 1/\sqrt{LC}, Z=RZ = R, cosϕ=1\cos\phi = 1.
  • Transformer: voltage ratio = turn ratio.
  • EM spectrum: ordering by frequency/wavelength.

Common Confusions and Traps

  • Magnetic force does no work — never increases KE of the particle.
  • The period in cyclotron is independent of speed and radius — but the cyclotron breaks down at relativistic speeds.
  • Lenz's law gives direction; Faraday gives magnitude.
  • Inductor opposes change in current, not the current itself.
  • In pure inductive or capacitive AC circuit, average power is zero (wattless).
  • cosϕ\cos\phi may be increased toward 1 by adding capacitor in parallel (power-factor correction).
  • Transformer cannot work with DC (no dΦ/dtd\Phi/dt).
  • EM waves carry momentum and exert radiation pressure.
  • For a moving charge in B\vec B, the path is a circle if vB\vec v \perp \vec B, helix if not.

Quick Revision Card

  • BB(infinite wire) =μ0I/(2πa)= \mu_0 I/(2\pi a).
  • BB(loop centre) =μ0I/(2R)= \mu_0 I/(2R).
  • Solenoid: B=μ0nIB = \mu_0 n I inside.
  • Cyclotron r=mv/(qB)r = mv/(qB), T=2πm/(qB)T = 2\pi m/(qB).
  • Two parallel wires: F/L=μ0I1I2/(2πd)F/L = \mu_0 I_1 I_2/(2\pi d), attractive if same direction.
  • Torque on loop: τ=NIABsinθ\tau = NIAB\sin\theta.
  • ε=dΦ/dt\varepsilon = -d\Phi/dt; motional ε=BLv\varepsilon = BLv.
  • Self-inductance solenoid: L=μ0n2AL = \mu_0 n^2 A\ell; energy 12LI2\tfrac{1}{2}LI^2.
  • RMS = peak/2/\sqrt{2}; average over half cycle = 2V0/π2V_0/\pi.
  • XL=ωLX_L = \omega L, XC=1/(ωC)X_C = 1/(\omega C).
  • LCR: Z=R2+(XLXC)2Z = \sqrt{R^2 + (X_L - X_C)^2}.
  • Resonance: ω0=1/LC\omega_0 = 1/\sqrt{LC}, cosϕ=1\cos\phi = 1.
  • Transformer: Vp/Vs=Np/NsV_p/V_s = N_p/N_s.
  • c=1/μ0ε0c = 1/\sqrt{\mu_0\varepsilon_0}; E0/B0=cE_0/B_0 = c.
  • EM spectrum: γ\gamma, X, UV, vis, IR, microwave, radio (decreasing freq).

Worked NEET Examples

Example 1: Field at Centre of a Loop

Single loop of radius 5 cm carrying 2 A:

B=μ0I/(2R)=(4π×107×2)/(0.1)=2.51×105 T.B = \mu_0 I/(2R) = (4\pi \times 10^{-7} \times 2)/(0.1) = 2.51 \times 10^{-5}\ \text{T}.

Example 2: Cyclotron Frequency

Proton in field B=1B = 1 T:

fc=qB/(2πm)=(1.6×1019×1)/(2π×1.67×1027)1.5×107 Hz=15 MHz.f_c = qB/(2\pi m) = (1.6 \times 10^{-19} \times 1)/(2\pi \times 1.67 \times 10^{-27}) \approx 1.5 \times 10^7\ \text{Hz} = 15\ \text{MHz}.

Example 3: Force on Wire

A wire of length 20 cm carrying 5 A makes 30° angle with magnetic field 0.4 T:

F=BILsinθ=0.4×5×0.2×0.5=0.2 N.F = BIL\sin\theta = 0.4 \times 5 \times 0.2 \times 0.5 = 0.2\ \text{N}.

Example 4: Motional EMF

A rod of length 0.5 m moves perpendicular to a field B=0.2B = 0.2 T at 4 m/s:

ε=BLv=0.2×0.5×4=0.4 V.\varepsilon = BLv = 0.2 \times 0.5 \times 4 = 0.4\ \text{V}.

Example 5: LCR Resonance

L = 10 mH, C = 1 μF. Resonance frequency:

f0=1/(2πLC)=1/(2π108)=1/(2π×104)1591 Hz.f_0 = 1/(2\pi\sqrt{LC}) = 1/(2\pi\sqrt{10^{-8}}) = 1/(2\pi \times 10^{-4}) \approx 1591\ \text{Hz}.

Derivations

Magnetic Field on Axis of Circular Loop

A loop of radius RR in xy-plane, current II. By Biot-Savart, at axial distance xx:

dB=(μ0/4π)IdLsin90°/r2cosα,dB = (\mu_0/4\pi) I dL \sin 90°/r^2 \cdot \cos\alpha,

where r=R2+x2r = \sqrt{R^2 + x^2} and cosα=R/r\cos\alpha = R/r gives the axial component. Integrating around the loop (dL=2πR\int dL = 2\pi R):

B=μ0IR2/[2(R2+x2)3/2].B = \mu_0 I R^2/[2(R^2 + x^2)^{3/2}].

At centre (x=0x = 0): B=μ0I/(2R)B = \mu_0 I/(2R).

Force Between Two Parallel Wires

Wire 1 at origin with current I1I_1 creates field at wire 2 (distance dd): B1=μ0I1/(2πd)B_1 = \mu_0 I_1/(2\pi d).

Force per unit length on wire 2: F/L=B1I2=μ0I1I2/(2πd)F/L = B_1 I_2 = \mu_0 I_1 I_2/(2\pi d).

Attractive when currents in same direction.

Self-Inductance of a Solenoid

A solenoid of length \ell, NN total turns, area AA. Field inside: B=μ0(N/)I=μ0nIB = \mu_0 (N/\ell) I = \mu_0 n I. Flux through one turn: Φ1=BA\Phi_1 = BA. Total flux linkage: NΦ1=Nμ0nIA=μ0n2IAN\Phi_1 = N\mu_0 n I A = \mu_0 n^2 I A \ell.

Self-inductance: L=NΦ1/I=μ0n2AL = N\Phi_1/I = \mu_0 n^2 A\ell.

EMF in a Rotating Coil

A coil of NN turns, area AA, rotating with angular velocity ω\omega in field BB has flux:

Φ=NBAcos(ωt).\Phi = NBA\cos(\omega t).

EMF:

ε=dΦ/dt=NBAωsin(ωt).\varepsilon = -d\Phi/dt = NBA\omega\sin(\omega t).

Peak EMF: ε0=NBAω\varepsilon_0 = NBA\omega. This is the basis of an AC generator.

Impedance of LCR

Voltage phasor magnitude across R: IRIR. Across L: IXL=IωLI X_L = I\omega L, leads I by 90°. Across C: IXC=I/(ωC)I X_C = I/(\omega C), lags I by 90°.

Net voltage: V0=I0R2+(XLXC)2=I0ZV_0 = I_0 \sqrt{R^2 + (X_L - X_C)^2} = I_0 Z, where Z=R2+(XLXC)2Z = \sqrt{R^2 + (X_L - X_C)^2} is impedance.

Phase angle: tanϕ=(XLXC)/R\tan\phi = (X_L - X_C)/R.

Resonance Condition

At XL=XCX_L = X_C, ωL=1/(ωC)\omega L = 1/(\omega C), so ω0=1/LC\omega_0 = 1/\sqrt{LC}.

At this frequency, Z=RZ = R (minimum), current is maximum, and VV is in phase with II (cosϕ=1\cos\phi = 1, max power).

Energy in Magnetic Field

Energy stored in inductor: U=(1/2)LI2U = (1/2) L I^2. Per unit volume:

u=B2/(2μ0).u = B^2/(2\mu_0).

For a solenoid with B=μ0nIB = \mu_0 n I, volume V=AV = A\ell:

U=uV=(μ0n2I2/2)(A)=(1/2)(μ0n2A)I2=(1/2)LI2.U = u \cdot V = (\mu_0 n^2 I^2/2)(A\ell) = (1/2)(\mu_0 n^2 A\ell) I^2 = (1/2) L I^2.

Consistent with L=μ0n2AL = \mu_0 n^2 A\ell.

Eddy Currents and Their Applications

When a conductor moves through a changing field, induced currents (eddies) circulate within it. By Lenz's law, they oppose the motion (magnetic braking).

Applications:

  • Electromagnetic brakes in trains.
  • Damping in galvanometers.
  • Induction heating.
  • Metal detectors.

Drawbacks:

  • Energy loss in transformer cores → laminated cores reduce this.

AC Power Details

Instantaneous power: p(t)=v(t)i(t)=V0I0sin(ωt)sin(ωtϕ)p(t) = v(t) i(t) = V_0 I_0 \sin(\omega t) \sin(\omega t - \phi).

Average over a cycle: Pˉ=VrmsIrmscosϕ\bar P = V_\text{rms} I_\text{rms} \cos\phi.

  • ϕ=0\phi = 0 (purely resistive): max power.
  • ϕ=π/2\phi = \pi/2 (purely L or C): zero average power.

Power factor cosϕ\cos\phi is improved by adding a capacitor in parallel with inductive load (common in industrial circuits to reduce reactive current).

Transformer Detailed Working

Two coils (primary and secondary) wound on a common iron core. Alternating current in primary creates alternating flux in core, which links secondary. By Faraday, EMF in secondary NsdΦ/dt\propto N_s d\Phi/dt.

For ideal transformer (no losses):

  • Vs/Vp=Ns/NpV_s/V_p = N_s/N_p (voltage ratio = turn ratio).
  • Is/Ip=Np/NsI_s/I_p = N_p/N_s (current inverse).
  • Ps=PpP_s = P_p (power conservation).

Why iron core? High permeability concentrates flux; lamination reduces eddy currents.

EM Spectrum Production and Uses

BandProductionUses
RadioOscillating dipoles, transmittersAM/FM, TV
MicrowaveKlystron, magnetronRadar, cell phones, ovens
IRHot bodies, lasersHeaters, remote, thermography
VisibleAtomic transitionsVision, optical comms
UVHigh-energy atoms, mercury arcSterilization, fluorescence
X-raysBombarding metalsImaging, crystallography
γ-raysNuclear transitionsCancer therapy, sterilisation

Formula Sheet

QuantityFormula
Biot-SavartdB=(μ0/4π)Idsinθ/r2dB = (\mu_0/4\pi) I\,d\ell\sin\theta/r^2
Long straight wireB=μ0I/(2πa)B = \mu_0 I/(2\pi a)
Circular loop (centre)B=μ0I/(2R)B = \mu_0 I/(2R)
Loop on axisB=μ0IR2/(2(R2+x2)3/2)B = \mu_0 I R^2/(2(R^2+x^2)^{3/2})
SolenoidB=μ0nIB = \mu_0 n I
ToroidB=μ0NI/(2πr)B = \mu_0 N I/(2\pi r)
Lorentz forceF=q(E+v×B)F = q(E + v \times B)
Cyclotron radiusr=mv/(qB)r = mv/(qB)
Cyclotron periodT=2πm/(qB)T = 2\pi m/(qB)
Force on wireF=BILsinθF = BIL\sin\theta
Parallel wiresF/L=μ0I1I2/(2πd)F/L = \mu_0 I_1 I_2/(2\pi d)
Torque on loopτ=NIABsinθ\tau = NIAB\sin\theta
Motional EMFε=BLv\varepsilon = BLv
Faradayε=dΦ/dt\varepsilon = -d\Phi/dt
Self-inductionε=LdI/dt\varepsilon = -L\,dI/dt
Solenoid LL=μ0n2AL = \mu_0 n^2 A\ell
Mutual inductionε2=MdI1/dt\varepsilon_2 = -M\,dI_1/dt
Inductor energyU=12LI2U = \tfrac{1}{2}LI^2
Energy density (B)u=B2/(2μ0)u = B^2/(2\mu_0)
RMSVrms=V0/2V_\text{rms} = V_0/\sqrt 2
Inductive reactanceXL=ωLX_L = \omega L
Capacitive reactanceXC=1/(ωC)X_C = 1/(\omega C)
LCR impedanceZ=R2+(XLXC)2Z = \sqrt{R^2 + (X_L - X_C)^2}
Resonanceω0=1/LC\omega_0 = 1/\sqrt{LC}
Q factorQ=ω0L/RQ = \omega_0 L/R
AC powerP=VrmsIrmscosϕP = V_\text{rms} I_\text{rms}\cos\phi
TransformerVp/Vs=Np/Ns=Is/IpV_p/V_s = N_p/N_s = I_s/I_p
Speed of EMc=1/μ0ε0c = 1/\sqrt{\mu_0\varepsilon_0}
E-B ratioE0/B0=cE_0/B_0 = c
Radiation pressurePabs=I/cP_\text{abs} = I/c

Sub-topics

6 pages

Practice quiz

Quiz
NEET Unit 11: Magnetism, EMI, AC and EM Waves — Quiz
15 questions · pick the best answer
Q1

Magnetic field at the centre of a circular loop of radius R carrying current I is:

Q2

A charged particle moves in a circle of radius r in magnetic field B. If B doubles, radius becomes:

Q3

RMS value of AC current with peak 10 A is:

Q4

At resonance in series LCR, impedance equals:

Q5

A transformer with 100 turns in primary and 1000 turns in secondary connected to 220 V AC. Output voltage is:

Q6

A long solenoid has 1000 turns/m and carries 2 A. Magnetic field inside is:

Q7

Lenz's law is a consequence of:

Q8

Assertion: Earth's magnetic field is due to currents in its molten outer core. Reason: Magnetic field is produced by moving charges.

Q9

An inductor L = 0.1 H, carrying 2 A current. Energy stored:

Q10

EM waves are:

Q11

Two parallel wires carrying currents in same direction:

Q12

In a series LCR circuit at resonance, the current and voltage are:

Q13

The frequency of resonance in LCR with L = 0.1 H and C = 10 μF is approximately:

Q14

Order of electromagnetic spectrum by INCREASING frequency:

Q15

Assertion: A wire carrying current in a magnetic field experiences a force. Reason: Moving charges in the wire feel Lorentz force.