Physics Lab

Unit 9: Oscillations and Waves

This is a 3–4 MCQ unit. SHM and waves are tightly knit through the formulas for period and energy. Doppler effect (for sound) is a near-certain NEET question. Beats and standing waves on strings/pipes also recur. Expect plenty of "find TT or ff" numericals.

Concept Map

  • Periodic and oscillatory motion
  • Simple Harmonic Motion
    • Kinematics (x, v, a)
    • Energy
    • Phase
  • Spring oscillator (series, parallel combinations)
  • Simple pendulum (small-angle derivation)
  • Damped and forced oscillations (qualitative)
  • Waves — transverse vs longitudinal
  • Wave equation, speed
  • Speed of sound — Laplace correction
  • Superposition, beats, standing waves
  • Resonance in pipes
  • Doppler effect for sound

Topic 1: Simple Harmonic Motion (SHM)

Sub-topic A: Definition

SHM is a periodic motion where the restoring force is proportional to displacement and directed toward the equilibrium:

F=kx,mx¨=kxx¨+ω2x=0,F = -kx, \quad m\ddot x = -kx \Rightarrow \ddot x + \omega^2 x = 0,

with ω=k/m\omega = \sqrt{k/m}.

Sub-topic B: Kinematics

General solution: x(t)=Asin(ωt+ϕ)x(t) = A\sin(\omega t + \phi) or x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t + \phi).

  • Amplitude: AA (max displacement).
  • Angular frequency: ω\omega (rad/s).
  • Time period: T=2π/ωT = 2\pi/\omega.
  • Frequency: f=1/Tf = 1/T.
  • Phase: (ωt+ϕ)(\omega t + \phi).

Velocity and acceleration:

v=Aωcos(ωt+ϕ),a=Aω2sin(ωt+ϕ)=ω2x.v = A\omega\cos(\omega t + \phi), \quad a = -A\omega^2\sin(\omega t + \phi) = -\omega^2 x.

vmax=Aω\vert v_\text{max}\vert = A\omega, amax=Aω2\vert a_\text{max}\vert = A\omega^2.

Useful relation: v=ωA2x2v = \omega\sqrt{A^2 - x^2}. Hence v2+ω2x2=ω2A2v^2 + \omega^2 x^2 = \omega^2 A^2.

Sub-topic C: Energy in SHM

K=12mω2(A2x2),U=12mω2x2,E=K+U=12mω2A2.K = \tfrac{1}{2} m \omega^2 (A^2 - x^2), \quad U = \tfrac{1}{2} m \omega^2 x^2, \quad E = K + U = \tfrac{1}{2} m \omega^2 A^2.

So total energy is constant and proportional to A2A^2. KE is maximum at x=0x = 0; PE is maximum at x=±Ax = \pm A.

Average over a full cycle: K=U=12E=14mω2A2\langle K \rangle = \langle U \rangle = \tfrac{1}{2} E = \tfrac{1}{4} m\omega^2 A^2.

Sub-topic D: Spring Oscillator

T=2πm/k,ω=k/m.T = 2\pi\sqrt{m/k}, \quad \omega = \sqrt{k/m}.

Series combination: 1/keq=1/k1+1/k21/k_\text{eq} = 1/k_1 + 1/k_2. Effective stiffness decreases ⟹ period increases.

Parallel combination: keq=k1+k2k_\text{eq} = k_1 + k_2. Stiffness adds ⟹ period decreases.

Sub-topic E: Simple Pendulum

For small angles (θ<10°\theta < 10°), torque =mgsinθmgθ= -mg\ell\sin\theta \approx -mg\ell\theta. So angular SHM with

T=2π/g.T = 2\pi\sqrt{\ell/g}.

Independent of mass and amplitude (to first order). On Earth's surface a pendulum's period varies with gg (so changes with altitude, depth, latitude).

For a pendulum on a freely falling lift, geff=0g_\text{eff} = 0 — it does not oscillate.

For a lift accelerating up with aa: geff=g+ag_\text{eff} = g + a, period decreases. Down: geff=gag_\text{eff} = g - a.

For a pendulum in a horizontally accelerating vehicle (acceleration aa): geff=g2+a2g_\text{eff} = \sqrt{g^2 + a^2}.

Sub-topic F: Damped and Forced Oscillations

Damped: amplitude decays as A(t)=A0ebt/(2m)A(t) = A_0 e^{-bt/(2m)} for weak damping. Energy decays as E0ebt/mE_0 e^{-bt/m}.

Forced oscillation: external periodic driving at frequency ωd\omega_d. Amplitude is maximum at resonance when ωdω0\omega_d \approx \omega_0 (natural frequency). Resonance amplitude is limited by damping.

Topic 2: Wave Motion

Sub-topic A: Types

  • Mechanical waves: need a medium (sound, water).
    • Transverse: oscillation \perp wave direction (string).
    • Longitudinal: oscillation \parallel wave direction (sound).
  • Electromagnetic waves: no medium needed.

Sub-topic B: Wave Parameters

A plane wave moving in +x+x direction:

y(x,t)=Asin(ωtkx+ϕ),y(x, t) = A\sin(\omega t - k x + \phi),

with k=2π/λk = 2\pi/\lambda (wave number), ω=2πf\omega = 2\pi f (angular frequency), wave speed v=ω/k=fλv = \omega/k = f\lambda.

Sub-topic C: Wave Speeds

  • On a stretched string of tension TT and linear mass density μ\mu:
v=T/μ.v = \sqrt{T/\mu}.
  • In a solid rod (longitudinal): v=Y/ρv = \sqrt{Y/\rho}.
  • In a fluid: v=K/ρv = \sqrt{K/\rho}.
  • In a gas (sound): v=γP/ρv = \sqrt{\gamma P/\rho} (Laplace), where γ=Cp/Cv\gamma = C_p/C_v. The earlier Newton formula v=P/ρv = \sqrt{P/\rho} used isothermal K=PK = P and underestimated by ~16%.

At 0 °C in air: v331 m/sv \approx 331\ \text{m/s}; at 20 °C, v343 m/sv \approx 343\ \text{m/s}. Temperature dependence: vTv \propto \sqrt{T} (kelvin).

Sub-topic D: Energy and Intensity

Energy density of a wave A2ω2\propto A^2 \omega^2. Intensity (power per unit area) A2\propto A^2. For point source: I1/r2I \propto 1/r^2.

Topic 3: Superposition and Standing Waves

Sub-topic A: Principle of Superposition

When two waves overlap, the net displacement is the algebraic sum of individual displacements.

Sub-topic B: Interference

Two coherent waves with same amplitude and frequency: y1=Asin(ωtkx)y_1 = A\sin(\omega t - kx), y2=Asin(ωtkx+ϕ)y_2 = A\sin(\omega t - kx + \phi). Result:

y=2Acos(ϕ/2)sin(ωtkx+ϕ/2).y = 2A\cos(\phi/2)\sin(\omega t - kx + \phi/2).

Resultant amplitude AR=2Acos(ϕ/2)A_R = 2A\vert \cos(\phi/2)\vert :

  • ϕ=0\phi = 0: constructive, AR=2AA_R = 2A.
  • ϕ=π\phi = \pi: destructive, AR=0A_R = 0.

Sub-topic C: Standing Waves on a String (both ends fixed)

A string of length LL supports modes with wavelengths λn=2L/n\lambda_n = 2L/n, n=1,2,3,n = 1, 2, 3, \dots. Frequencies:

fn=nv2L=n2LT/μ.f_n = \frac{n v}{2 L} = \frac{n}{2L}\sqrt{T/\mu}.
  • n=1n = 1: fundamental (1st harmonic).
  • n=2n = 2: 2nd harmonic (or 1st overtone).
  • n=3n = 3: 3rd harmonic (or 2nd overtone).

All integer harmonics are present.

Sub-topic D: Standing Waves in a Pipe

Open at both ends (open organ pipe): all harmonics

fn=nv2L,n=1,2,3,.f_n = \frac{n v}{2 L}, \quad n = 1, 2, 3, \dots.

Closed at one end (closed organ pipe): only odd harmonics

fn=(2n1)v4L,n=1,2,3,.f_n = \frac{(2n - 1) v}{4 L}, \quad n = 1, 2, 3, \dots.

Hence for the same LL, the closed pipe has half the fundamental of the open pipe.

End correction (open end): add 0.6r0.6 r to LL for a tube of radius rr.

Sub-topic E: Beats

When two sound waves of nearly equal frequencies f1,f2f_1, f_2 interfere, the result has a slow envelope:

y=2Acos(2πfbeatt/2)cos(2πfavgt),y = 2A\cos(2\pi f_\text{beat} t/2)\cos(2\pi f_\text{avg} t),

with beat frequency

fbeat=f1f2.f_\text{beat} = |f_1 - f_2|.

Human ear can perceive beats for f1f210 Hz\vert f_1 - f_2\vert \lesssim 10\ \text{Hz}.

Topic 4: Doppler Effect for Sound

For a source SS and observer OO moving along the line joining them, with speed of sound vv, source speed vsv_s, observer speed vov_o:

f=fv+vovvs.f' = f \cdot \frac{v + v_o}{v - v_s}.

Sign convention (take direction from observer to source as positive):

  • vo>0v_o > 0 if observer moves toward source.
  • vs>0v_s > 0 if source moves toward observer.

Special cases:

  • Source approaching, observer stationary: f=fv/(vvs)f' = f\cdot v/(v - v_s), ff' increases.
  • Source receding: f=fv/(v+vs)f' = f\cdot v/(v + v_s), ff' decreases.
  • Observer approaching stationary source: f=f(v+vo)/vf' = f(v + v_o)/v.
  • Observer receding: f=f(vvo)/vf' = f(v - v_o)/v.

Wind: if wind blows with speed ww from source to observer, replace vv by v+wv + w in numerator and denominator.

Doppler effect for sound is not symmetric in source vs observer motion (unlike light Doppler, which is symmetric to first order). This is because sound has a preferred frame (medium).

NEET Pattern MCQ Tips

  • SHM period: spring T=2πm/kT = 2\pi\sqrt{m/k}, pendulum T=2π/gT = 2\pi\sqrt{\ell/g}.
  • SHM energy: E=12mω2A2E = \tfrac{1}{2} m\omega^2 A^2.
  • Spring combinations: series vs parallel.
  • Standing waves: open vs closed pipes; harmonics present.
  • Beats: fb=f1f2f_b = \vert f_1 - f_2\vert ; loading with wax/dust to identify the higher frequency.
  • Doppler effect: source/observer moving — apply formula with correct sign.
  • Wave on string: v=T/μv = \sqrt{T/\mu}.
  • Laplace's correction: v=γP/ρv = \sqrt{\gamma P/\rho}.

Common Confusions and Traps

  • SHM amplitude does not appear in the period.
  • A simple pendulum's period is independent of mass.
  • For SHM, a=ω2xa = -\omega^2 x — the negative sign is essential (restoring).
  • Closed organ pipe contains only odd harmonics; open pipe contains all.
  • Doppler effect for sound depends on whether the medium moves — wind alters the result.
  • Beat frequency is the absolute difference of frequencies — independent of which is larger.
  • Wave on a string carries transverse displacement, but propagates longitudinally along the string.
  • The Laplace correction multiplies Newton's formula by γ\sqrt{\gamma}, fixing the ~16% discrepancy.

Quick Revision Card

  • x¨+ω2x=0\ddot x + \omega^2 x = 0; T=2π/ωT = 2\pi/\omega.
  • Spring: T=2πm/kT = 2\pi\sqrt{m/k}.
  • Pendulum: T=2π/gT = 2\pi\sqrt{\ell/g}.
  • SHM energy: E=12mω2A2E = \tfrac{1}{2} m\omega^2 A^2.
  • vmax=Aωv_\text{max} = A\omega; amax=Aω2a_\text{max} = A\omega^2.
  • Series springs: 1/keq=1/k1+1/k21/k_\text{eq} = 1/k_1 + 1/k_2.
  • Parallel: keq=k1+k2k_\text{eq} = k_1 + k_2.
  • Wave: v=fλ=ω/kv = f\lambda = \omega/k.
  • String: v=T/μv = \sqrt{T/\mu}.
  • Sound in gas: v=γP/ρv = \sqrt{\gamma P/\rho}, vTv \propto \sqrt{T}.
  • Open pipe: all harmonics; closed pipe: odd harmonics.
  • Doppler (sound): f=f(v+vo)/(vvs)f' = f(v + v_o)/(v - v_s).
  • Beats: fb=f1f2f_b = \vert f_1 - f_2\vert .

Worked NEET Examples

Example 1: Maximum Velocity and Acceleration

A particle in SHM with amplitude 4 cm and period 0.5 s. Angular frequency: ω=2π/T=4π\omega = 2\pi/T = 4\pi rad/s. Maximum velocity: vmax=Aω=0.04×4π0.5v_\text{max} = A\omega = 0.04 \times 4\pi \approx 0.5 m/s. Maximum acceleration: amax=Aω2=0.04×16π26.3a_\text{max} = A\omega^2 = 0.04 \times 16\pi^2 \approx 6.3 m/s².

Example 2: Pendulum Period on Moon

On Earth: TE=2πL/9.8T_E = 2\pi\sqrt{L/9.8}. On Moon: TM=2πL/1.62T_M = 2\pi\sqrt{L/1.62}. Ratio: TM/TE=9.8/1.62=6.042.46T_M/T_E = \sqrt{9.8/1.62} = \sqrt{6.04} \approx 2.46. So Moon pendulum has ~2.5× longer period.

Example 3: Standing Wave on String

A string of length 1 m, mass per unit length 0.01 kg/m, tension 100 N. Wave speed: v=T/μ=10000=100v = \sqrt{T/\mu} = \sqrt{10000} = 100 m/s. Fundamental: f1=v/(2L)=50f_1 = v/(2L) = 50 Hz. Second harmonic: 100 Hz, third: 150 Hz, etc.

Example 4: Beat Frequency

Two tuning forks 250 Hz and 256 Hz. Beats per second: 6.

Example 5: Doppler — Train Approaching

Train horn at 600 Hz approaching observer at 30 m/s; speed of sound 340 m/s. Observer hears:

f=600×340/(34030)=600×340/310658 Hz.f' = 600 \times 340/(340 - 30) = 600 \times 340/310 \approx 658\ \text{Hz}.

After passing, f=600×340/(340+30)552f' = 600 \times 340/(340 + 30) \approx 552 Hz. Drop in pitch: 658552658 \to 552 Hz.

Derivations

SHM from F = −kx

Newton's law: mx¨=kxm\ddot x = -kx. Define ω2=k/m\omega^2 = k/m. Then x¨+ω2x=0\ddot x + \omega^2 x = 0. Solution: x(t)=Acos(ωt+ϕ)x(t) = A\cos(\omega t + \phi). Period: T=2π/ω=2πm/kT = 2\pi/\omega = 2\pi\sqrt{m/k}.

Pendulum Period (Small Angle)

For a pendulum of length LL, displacement angle θ\theta (small), restoring force tangent to circle: Ft=mgsinθmgθF_t = -mg\sin\theta \approx -mg\theta. Tangential distance: s=Lθs = L\theta, so s¨=Lθ¨\ddot s = L\ddot\theta, and Newton's law gives mLθ¨=mgθm L\ddot\theta = -mg\theta, so θ¨+(g/L)θ=0\ddot\theta + (g/L)\theta = 0, period T=2πL/gT = 2\pi\sqrt{L/g}.

Wave Equation

For a string, transverse displacement y(x,t)y(x, t) satisfies

2yt2=v22yx2.\frac{\partial^2 y}{\partial t^2} = v^2 \frac{\partial^2 y}{\partial x^2}.

A traveling wave solution: y=Asin(ωtkx)y = A\sin(\omega t - kx) with v=ω/kv = \omega/k.

For string, v=T/μv = \sqrt{T/\mu} (derive by Newton's law on a small string element).

Speed of Sound in Gas

Newton's formula: v=P/ρv = \sqrt{P/\rho} (assumed isothermal). Predicted ~280 m/s in air at 0 °C — 15% too low.

Laplace's correction: Process is actually adiabatic (fast oscillations, no heat flow). For adiabatic, ΔP/ΔV=γP/V\Delta P/\Delta V = -\gamma P/V, so bulk modulus is γP\gamma P. Hence

v=γP/ρ=γRT/M.v = \sqrt{\gamma P/\rho} = \sqrt{\gamma RT/M}.

For diatomic (γ=7/5\gamma = 7/5) at 273 K: v=1.4×8.314×273/0.029331v = \sqrt{1.4 \times 8.314 \times 273/0.029} \approx 331 m/s — matches experiment.

Doppler Effect — Source Approaches Stationary Observer

Source emits waves of frequency ff. In a time Δt=1/f\Delta t = 1/f, source moves vs/fv_s/f closer. So consecutive wavefronts are separated by λ=(vvs)/f\lambda' = (v - v_s)/f (where vv is sound speed). Observer hears

f=v/λ=fv/(vvs).f' = v/\lambda' = f v/(v - v_s).

Higher pitch as source approaches.

Energy in SHM

Total energy:

E=12mω2A2.E = \tfrac{1}{2} m \omega^2 A^2.

KE: K=12mv2=12mω2(A2x2)K = \tfrac{1}{2} m v^2 = \tfrac{1}{2} m \omega^2 (A^2 - x^2).

PE: U=12kx2=12mω2x2U = \tfrac{1}{2} k x^2 = \tfrac{1}{2} m \omega^2 x^2.

Both K and U oscillate with frequency 2ω2\omega (double the SHM frequency).

Average over a cycle: K=U=E/2\langle K \rangle = \langle U \rangle = E/2.

Pendulum Variants

Compound Pendulum

A rigid body pivoted at point P, distance \ell from CM, MI about pivot IPI_P. Period for small oscillations:

T=2πIP/(Mg).T = 2\pi\sqrt{I_P/(M g \ell)}.

Torsion Pendulum

A disc suspended by a wire with torsion constant CC. Period:

T=2πI/C.T = 2\pi\sqrt{I/C}.

Liquid in U-Tube

A liquid column of length \ell in a uniform U-tube. Oscillates with period

T=2π/(2g).T = 2\pi\sqrt{\ell/(2g)}.

Wave on a Stretched String — Modes

For a string of length LL fixed at both ends, modes have wavelengths λn=2L/n\lambda_n = 2L/n, so frequencies

fn=(n/2L)T/μ.f_n = (n/2L)\sqrt{T/\mu}.

For a string fixed at one end, free at other: λn=4L/(2n1)\lambda_n = 4L/(2n-1) — only odd harmonics, similar to closed pipe.

Doppler Effect — Source and Observer Both Moving

General formula:

f=fv+vovvs,f' = f \frac{v + v_o}{v - v_s},

with sign convention: positive when moving toward each other.

If wind has speed ww blowing from source to observer, replace vv by v+wv + w.

EM Wave Doppler vs Sound Doppler

For sound (with medium), source and observer are not symmetric. For EM (no medium), Doppler effect depends only on relative velocity:

f=f(1β)/(1+β),β=v/c.f' = f\sqrt{(1-\beta)/(1+\beta)}, \quad \beta = v/c.

For non-relativistic speeds: Δf/f±v/c\Delta f/f \approx \pm v/c. Sign + for approach, − for recede.

Resonance Tube Experiments

For determining sound speed: a resonance tube partially filled with water, vibrating tuning fork held above open top. As water level drops, resonance occurs at length L1,L2,L_1, L_2, \dots where L=(n1/4)λL = (n - 1/4)\lambda. Difference L2L1=λ/2L_2 - L_1 = \lambda/2. Hence v=2f(L2L1)v = 2f(L_2 - L_1).

End correction: 0.3d0.3 \cdot d (d = inner diameter).

Formula Sheet

QuantityFormula
SHM displacementx=Asin(ωt+ϕ)x = A\sin(\omega t + \phi)
SHM velocityv=Aωcos(ωt+ϕ)v = A\omega\cos(\omega t + \phi)
SHM accelerationa=ω2xa = -\omega^2 x
Velocity-positionv=ωA2x2v = \omega\sqrt{A^2 - x^2}
Total energyE=12mω2A2E = \tfrac{1}{2}m\omega^2 A^2
Spring SHM periodT=2πm/kT = 2\pi\sqrt{m/k}
Pendulum periodT=2π/gT = 2\pi\sqrt{\ell/g}
Pendulum in lift upT=2π/(g+a)T = 2\pi\sqrt{\ell/(g+a)}
Pendulum in accelerating carT=2π/g2+a2T = 2\pi\sqrt{\ell/\sqrt{g^2+a^2}}
Series springs1/keq=1/k1+1/k21/k_\text{eq} = 1/k_1 + 1/k_2
Parallel springskeq=k1+k2k_\text{eq} = k_1 + k_2
Damped amplitudeA(t)=A0ebt/(2m)A(t) = A_0 e^{-bt/(2m)}
Wave equationy=Asin(ωtkx)y = A\sin(\omega t - kx)
Wave speedv=fλ=ω/kv = f\lambda = \omega/k
String wavev=T/μv = \sqrt{T/\mu}
Sound in gasv=γP/ρ=γRT/Mv = \sqrt{\gamma P/\rho} = \sqrt{\gamma RT/M}
Open pipe harmonicsfn=nv/(2L)f_n = nv/(2L)
Closed pipe harmonicsfn=(2n1)v/(4L)f_n = (2n-1)v/(4L)
Beatsfb=f1f2f_b = \|f_1 - f_2\|
Doppler (sound)f=f(v+vo)/(vvs)f' = f(v + v_o)/(v - v_s)

Sub-topics

6 pages

Practice quiz

Quiz
NEET Unit 9: Oscillations and Waves — Quiz
15 questions · pick the best answer
Q1

Time period of a simple pendulum of length L on a planet where g is g/4 compared to Earth's is:

Q2

A spring-mass system has time period 2 s. If the mass is quadrupled, the new time period is:

Q3

A particle executes SHM with amplitude A and angular frequency ω. Its maximum velocity is:

Q4

The speed of sound in air at 20 °C is approximately 343 m/s. At 100 °C, it becomes (using v ∝ √T in kelvin):

Q5

Two tuning forks of frequencies 256 Hz and 260 Hz are sounded together. Beats per second heard are:

Q6

The fundamental frequency of a closed organ pipe of length L is f. The fundamental of an open pipe of same length is:

Q7

A source of sound moves toward a stationary observer with speed 30 m/s. If sound speed is 330 m/s and source frequency is 300 Hz, observer hears:

Q8

Energy in SHM is proportional to:

Q9

Two springs of constants k and 2k connected in series. Effective stiffness:

Q10

Assertion: A simple pendulum does not work in a freely falling lift. Reason: In free fall the effective g is zero.

Q11

A stretched string of length L vibrates in its 3rd harmonic. Its frequency relative to fundamental f₁ is:

Q12

A wave on a string has T = 1 N and μ = 0.01 kg/m. Wave speed is:

Q13

If a tuning fork of 256 Hz gives 4 beats per second with another fork, and on loading the second fork with wax the beats reduce to 2 per second, the unknown frequency is:

Q14

Closed organ pipe of length L has fundamental f. What harmonics are present?

Q15

Assertion: Sound waves cannot travel in vacuum. Reason: Sound is a longitudinal wave that requires a material medium.