Physics Lab

Vector Addition

Vectors obey rules of geometry, not arithmetic. To add forces, velocities or displacements you must respect direction. The triangle and parallelogram laws give magnitude and direction in closed form, while component resolution turns any sum into easy algebra.

Concept

Triangle law: Place the tail of b⃗\vec b at the tip of a⃗\vec a. The sum a⃗+b⃗\vec a + \vec b runs from the start to the final tip.

Parallelogram law: Place tails of a⃗,b⃗\vec a, \vec b together; the diagonal of the parallelogram from the common point is a⃗+b⃗\vec a + \vec b.

Component form: a⃗=axi^+ayj^\vec a = a_x\hat i + a_y\hat j, b⃗=bxi^+byj^\vec b = b_x\hat i + b_y\hat j, so a⃗+b⃗=(ax+bx)i^+(ay+by)j^\vec a + \vec b = (a_x + b_x)\hat i + (a_y + b_y)\hat j.

If θ\theta is the angle between a⃗\vec a and b⃗\vec b, ∣a⃗+b⃗∣=a2+b2+2abcos⁡θ.|\vec a + \vec b| = \sqrt{a^{2} + b^{2} + 2 a b \cos\theta}.

The resultant makes angle α\alpha with a⃗\vec a where tan⁡α=bsin⁡θa+bcos⁡θ\tan\alpha = \dfrac{b\sin\theta}{a + b\cos\theta}.

Derivation

Drop a perpendicular from the tip of b⃗\vec b onto the line of a⃗\vec a extended. The component along a⃗\vec a is bcos⁡θb\cos\theta; perpendicular is bsin⁡θb\sin\theta. By Pythagoras on the right triangle formed by a+bcos⁡θa + b\cos\theta and bsin⁡θb\sin\theta: R2=(a+bcos⁡θ)2+(bsin⁡θ)2=a2+2abcos⁡θ+b2.R^{2} = (a + b\cos\theta)^{2} + (b\sin\theta)^{2} = a^{2} + 2ab\cos\theta + b^{2}. The direction follows from tan⁡α=bsin⁡θ/(a+bcos⁡θ)\tan\alpha = b\sin\theta/(a + b\cos\theta).

Extremes: θ=0\theta = 0 gives R=a+bR = a + b (maximum); θ=π\theta = \pi gives R=∣a−b∣R = |a - b| (minimum); θ=π/2\theta = \pi/2 gives R=a2+b2R = \sqrt{a^{2}+b^{2}}.

JEE Worked Example

Q. Two forces F⃗1\vec F_1 and F⃗2\vec F_2 act at a point with magnitudes 5 N5\,\text{N} and 12 N12\,\text{N} inclined at 90∘90^\circ. Find the magnitude and direction of the resultant.

Solution. R=52+122=13 NR = \sqrt{5^{2} + 12^{2}} = 13\,\text{N}. Angle with F⃗1\vec F_1: tan⁡α=12/5\tan\alpha = 12/5, so α=tan⁡−1(12/5)≈67.4∘\alpha = \tan^{-1}(12/5) \approx 67.4^\circ.

Traps

  • Adding magnitudes scalarly when directions differ.
  • Forgetting that Rmin⁡=∣a−b∣R_{\min} = |a - b| may be zero only if a=ba = b and θ=π\theta = \pi.
  • Using the parallelogram formula with the supplementary angle (always use the angle between when both tails coincide).
  • Mixing degrees and radians in a calculator.

Key Takeaways

  • Resolve into perpendicular components for any non-trivial sum.
  • Memorise R2=a2+b2+2abcos⁡θR^{2} = a^{2} + b^{2} + 2ab\cos\theta and its extremes.
  • Direction comes from tan⁡α=bsin⁡θ/(a+bcos⁡θ)\tan\alpha = b\sin\theta/(a + b\cos\theta).

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