Physics Lab

Degrees of Freedom

A degree of freedom (DOF) is an independent way in which a molecule can store energy. The number of degrees of freedom directly controls the molar heat capacities CvC_v and CpC_p and hence the adiabatic ratio γ\gamma.

Concept

For a single molecule:

  • Translation: 3 DOF (motion along xx, yy, zz).
  • Rotation: depends on geometry.
  • Vibration: each vibrational mode counts as 2 DOF (kinetic + potential).

Monatomic gas (He, Ar, Ne)

  • 3 translational DOF.
  • Rotation about an axis through the centre carries no significant moment of inertia for a point-like atom.
  • No vibration.
  • Total f=3f = 3.

Diatomic gas (O2_2, N2_2, H2_2) — rigid rotator at moderate TT

  • 3 translational + 2 rotational (perpendicular to bond axis) DOF.
  • Rotation about the bond axis is negligible (very small moment of inertia).
  • Vibration is frozen out at room temperature.
  • Total f=5f = 5.

At high temperatures vibration becomes excited: add 2 more DOF, giving f=7f = 7.

Polyatomic gas (non-linear: H2_2O, CH4_4)

  • 3 translational + 3 rotational DOF.
  • Plus any active vibrational modes.
  • Total at moderate T f=6f = 6.

Heat capacities

By equipartition (next sub-topic), each DOF contributes 12R\tfrac{1}{2} R to CvC_v per mole:

Cv=f2R,Cp=Cv+R=f+22R,γ=CpCv=1+2fC_v = \frac{f}{2} R, \quad C_p = C_v + R = \frac{f+2}{2} R, \quad \gamma = \frac{C_p}{C_v} = 1 + \frac{2}{f}

Gas typeffCvC_vCpC_pγ\gamma
Monatomic332R\tfrac{3}{2}R52R\tfrac{5}{2}R1.67
Diatomic552R\tfrac{5}{2}R72R\tfrac{7}{2}R1.40
Polyatomic63R3R4R4R1.33

Worked Example

Q: A gas has γ=1.40\gamma = 1.40. Identify the type of gas and compute its CvC_v and CpC_p in J/(mol·K).

A: γ=1+2/f=1.402/f=0.40f=5\gamma = 1 + 2/f = 1.40 \Rightarrow 2/f = 0.40 \Rightarrow f = 5. Diatomic gas (e.g., N2_2, O2_2).

  • Cv=(5/2)R=(5/2)(8.314)20.8C_v = (5/2)R = (5/2)(8.314) \approx 20.8 J/(mol·K).
  • Cp=(7/2)R29.1C_p = (7/2)R \approx 29.1 J/(mol·K).

Q2: Why is the measured γ\gamma for H2_2 at very low temperatures closer to 5/3 than to 7/5?

A: At low TT, even rotational modes get "frozen out" (quantum mechanics — rotational quanta become comparable to kBTk_B T), so only 3 translational DOF remain active. γ1+2/3=5/3\gamma \to 1 + 2/3 = 5/3.

Common Confusions

  • Each vibrational mode contributes 2 DOF (one KE, one PE), not 1.
  • For a linear molecule, only 2 rotational DOF count, not 3 — rotation about the bond axis has negligible moment of inertia.
  • DOF can be temperature-dependent: at low TT rotations may freeze; at very high TT vibrations switch on.

Key Takeaways

  • Cv=f2RC_v = \tfrac{f}{2} R and γ=1+2/f\gamma = 1 + 2/f.
  • Monatomic: f=3f = 3, γ=5/3\gamma = 5/3. Diatomic (rigid): f=5f = 5, γ=7/5\gamma = 7/5. Polyatomic: f6f \ge 6, γ4/3\gamma \le 4/3.
  • More DOF \Rightarrow more "energy storage capacity" per molecule \Rightarrow larger CvC_v and smaller γ\gamma.

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