Physics Lab

Atmospheric Pressure

The Earth's atmosphere exerts pressure on every surface due to the weight of air above. Standard atmospheric pressure at sea level is approximately 1.013×1051.013 \times 10^5 Pa = 760 mm of Hg = 1 atm.

Concept

Torricelli (1643) measured atmospheric pressure using a tube filled with mercury inverted into a mercury reservoir. The height hh of the mercury column corresponds to atmospheric pressure: Patm=ρHggh.P_{\text{atm}} = \rho_{\text{Hg}}\,g\,h.

With ρHg=13600\rho_{\text{Hg}} = 13600 kg/m3^3, g=9.8g=9.8 m/s2^2, h=0.76h=0.76 m: Patm1.013×105P_{\text{atm}} \approx 1.013 \times 10^5 Pa.

Manometer (open-tube U-shaped): measures gauge pressure of a gas by the height difference of liquid in the two arms: Pgas=Patm+ρgh.P_{\text{gas}} = P_{\text{atm}} + \rho g h.

Derivation

For the mercury barometer:

  1. The closed top of the tube above the mercury column is essentially vacuum (vapour pressure negligible).
  2. At the level of mercury in the reservoir, pressure inside the tube = pressure outside = PatmP_{\text{atm}}.
  3. From hydrostatics: Pvacuum+ρHggh=PatmP_{\text{vacuum}} + \rho_{\text{Hg}} g h = P_{\text{atm}}, giving Patm=ρHgghP_{\text{atm}} = \rho_{\text{Hg}} g h.

The height is independent of the tube cross-section or orientation (as long as the tube is long enough).

Worked Example

A patient's blood pressure is reported as 120/80 mm Hg. Convert systolic 120 mm Hg to Pa.

P=ρgh=13600×9.8×0.120=1.6×104Pa.P = \rho g h = 13600 \times 9.8 \times 0.120 = 1.6 \times 10^{4}\,\text{Pa}.

This is the gauge pressure (above atmospheric).

Common Confusions

  • A barometer reading 760760 mm Hg means atmospheric pressure pushes mercury up by that height — there is no air pushing it down inside the tube.
  • The reading does not depend on tube area; only height matters.
  • Pressure decreases with altitude — by about 1 mm Hg per 11 m near sea level.

Key Takeaways

  • Patm1.013×105P_{\text{atm}} \approx 1.013 \times 10^5 Pa = 760 mm Hg = 1 atm.
  • Mercury barometer: h=Patm/(ρg)h = P_{\text{atm}}/(\rho g).
  • Manometer measures gauge pressure via height difference.

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